Base | Representation |
---|---|
bin | 110000000000001100111011… |
… | …111000111010111100011101 |
3 | 1000200111212221022102100220021 |
4 | 300000030323320322330131 |
5 | 210132443002241242000 |
6 | 2025003124544552141 |
7 | 62316632303460130 |
oct | 6000147370727435 |
9 | 1020455838370807 |
10 | 211120122212125 |
11 | 612a65a510a135 |
12 | 1b8185b1922651 |
13 | 90a5707cba059 |
14 | 3a1c3a8836217 |
15 | 1961abb2e011a |
hex | c0033be3af1d |
211120122212125 has 32 divisors (see below), whose sum is σ = 307524372120576. Its totient is φ = 141687911779200.
The previous prime is 211120122212099. The next prime is 211120122212141. The reversal of 211120122212125 is 521212221021112.
211120122212125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 211120122212125 - 221 = 211120120114973 is a prime.
It is a super-3 number, since 3×2111201222121253 (a number of 44 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 211120122212125.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2566768872 + ... + 2566851121.
It is an arithmetic number, because the mean of its divisors is an integer number (9610136628768).
Almost surely, 2211120122212125 is an apocalyptic number.
211120122212125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
211120122212125 is a deficient number, since it is larger than the sum of its proper divisors (96404249908451).
211120122212125 is an equidigital number, since it uses as much as digits as its factorization.
211120122212125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5133620062 (or 5133620052 counting only the distinct ones).
The product of its (nonzero) digits is 640, while the sum is 25.
Adding to 211120122212125 its reverse (521212221021112), we get a palindrome (732332343233237).
The spelling of 211120122212125 in words is "two hundred eleven trillion, one hundred twenty billion, one hundred twenty-two million, two hundred twelve thousand, one hundred twenty-five".
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