Base | Representation |
---|---|
bin | 1100010010011111011… |
… | …0100001000011000111 |
3 | 202011221110021211100222 |
4 | 3010213312201003013 |
5 | 11424334213000241 |
6 | 240553233054555 |
7 | 21152541251123 |
oct | 3044766410307 |
9 | 664843254328 |
10 | 211122000071 |
11 | 815999574a4 |
12 | 34b003b745b |
13 | 16ba75c0bc8 |
14 | a30b26c583 |
15 | 5759ab1a4b |
hex | 3127da10c7 |
211122000071 has 2 divisors, whose sum is σ = 211122000072. Its totient is φ = 211122000070.
The previous prime is 211122000013. The next prime is 211122000079. The reversal of 211122000071 is 170000221112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211122000071 - 210 = 211121999047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211122000079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105561000035 + 105561000036.
It is an arithmetic number, because the mean of its divisors is an integer number (105561000036).
Almost surely, 2211122000071 is an apocalyptic number.
211122000071 is a deficient number, since it is larger than the sum of its proper divisors (1).
211122000071 is an equidigital number, since it uses as much as digits as its factorization.
211122000071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 211122000071 its reverse (170000221112), we get a palindrome (381122221183).
The spelling of 211122000071 in words is "two hundred eleven billion, one hundred twenty-two million, seventy-one", and thus it is an aban number.
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