Base | Representation |
---|---|
bin | 110000000000001110101100… |
… | …011010010000101000100011 |
3 | 1000200112001210212121220220021 |
4 | 300000032230122100220203 |
5 | 210133010334024444112 |
6 | 2025004040142454311 |
7 | 62320030135424446 |
oct | 6000165432205043 |
9 | 1020461725556807 |
10 | 211122009999907 |
11 | 612a7383784026 |
12 | 1b818a39b94397 |
13 | 90a5949136146 |
14 | 3a1c50744165d |
15 | 1961b7bdd9907 |
hex | c003ac690a23 |
211122009999907 has 2 divisors, whose sum is σ = 211122009999908. Its totient is φ = 211122009999906.
The previous prime is 211122009999877. The next prime is 211122010000007. The reversal of 211122009999907 is 709999900221112.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211122009999907 - 215 = 211122009967139 is a prime.
It is a super-2 number, since 2×2111220099999072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211122009999007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105561004999953 + 105561004999954.
It is an arithmetic number, because the mean of its divisors is an integer number (105561004999954).
Almost surely, 2211122009999907 is an apocalyptic number.
211122009999907 is a deficient number, since it is larger than the sum of its proper divisors (1).
211122009999907 is an equidigital number, since it uses as much as digits as its factorization.
211122009999907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3306744, while the sum is 61.
The spelling of 211122009999907 in words is "two hundred eleven trillion, one hundred twenty-two billion, nine million, nine hundred ninety-nine thousand, nine hundred seven".
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