Base | Representation |
---|---|
bin | 10011101010011000… |
… | …101100011101011101 |
3 | 2000111100100110022121 |
4 | 103222120230131131 |
5 | 321214211230133 |
6 | 13410535542541 |
7 | 1345115556265 |
oct | 235230543535 |
9 | 60440313277 |
10 | 21112211293 |
11 | 8a54324908 |
12 | 411252aa51 |
13 | 1cb5c42824 |
14 | 1043cc27a5 |
15 | 83871502d |
hex | 4ea62c75d |
21112211293 has 2 divisors, whose sum is σ = 21112211294. Its totient is φ = 21112211292.
The previous prime is 21112211291. The next prime is 21112211339. The reversal of 21112211293 is 39211221112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20851937604 + 260273689 = 144402^2 + 16133^2 .
It is a cyclic number.
It is not a de Polignac number, because 21112211293 - 21 = 21112211291 is a prime.
Together with 21112211291, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21112211291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556105646 + 10556105647.
It is an arithmetic number, because the mean of its divisors is an integer number (10556105647).
Almost surely, 221112211293 is an apocalyptic number.
It is an amenable number.
21112211293 is a deficient number, since it is larger than the sum of its proper divisors (1).
21112211293 is an equidigital number, since it uses as much as digits as its factorization.
21112211293 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432, while the sum is 25.
The spelling of 21112211293 in words is "twenty-one billion, one hundred twelve million, two hundred eleven thousand, two hundred ninety-three".
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