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211130013020 = 22510556500651
BaseRepresentation
bin1100010010100001010…
…1000101010101011100
3202011222000100221001212
43010220111011111130
511424343240404040
6240554120523552
721152666333363
oct3045025052534
9664860327055
10211130013020
11815a342a773
1234b030205b8
1316ba91681b4
14a30c3567da
15575a645d65
hex312854555c

211130013020 has 12 divisors (see below), whose sum is σ = 443373027384. Its totient is φ = 84452005200.

The previous prime is 211130012987. The next prime is 211130013041. The reversal of 211130013020 is 20310031112.

It is a junction number, because it is equal to n+sod(n) for n = 211130012986 and 211130013004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5278250306 + ... + 5278250345.

It is an arithmetic number, because the mean of its divisors is an integer number (36947752282).

Almost surely, 2211130013020 is an apocalyptic number.

211130013020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

211130013020 is an abundant number, since it is smaller than the sum of its proper divisors (232243014364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211130013020 is a wasteful number, since it uses less digits than its factorization.

211130013020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10556500660 (or 10556500658 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 211130013020 its reverse (20310031112), we get a palindrome (231440044132).

The spelling of 211130013020 in words is "two hundred eleven billion, one hundred thirty million, thirteen thousand, twenty".

Divisors: 1 2 4 5 10 20 10556500651 21113001302 42226002604 52782503255 105565006510 211130013020