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2111300203 = 2391795661
BaseRepresentation
bin111110111010111…
…1110001001101011
312110010210011101211
41331311332021223
513310443101303
6545300253551
7103214520115
oct17565761153
95403704354
102111300203
11993857101
124ab0a12b7
1327854647c
1416058c3b5
15c554a66d
hex7dd7e26b

2111300203 has 4 divisors (see below), whose sum is σ = 2203095888. Its totient is φ = 2019504520.

The previous prime is 2111300183. The next prime is 2111300221. The reversal of 2111300203 is 3020031112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111300203 - 25 = 2111300171 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111300293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45897808 + ... + 45897853.

It is an arithmetic number, because the mean of its divisors is an integer number (550773972).

Almost surely, 22111300203 is an apocalyptic number.

2111300203 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

2111300203 is a deficient number, since it is larger than the sum of its proper divisors (91795685).

2111300203 is an equidigital number, since it uses as much as digits as its factorization.

2111300203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91795684.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 2111300203 is about 45948.8868526758. The cubic root of 2111300203 is about 1282.8720103531.

Adding to 2111300203 its reverse (3020031112), we get a palindrome (5131331315).

The spelling of 2111300203 in words is "two billion, one hundred eleven million, three hundred thousand, two hundred three".

Divisors: 1 23 91795661 2111300203