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211130121035 = 5386310930889
BaseRepresentation
bin1100010010100001010…
…1011111101101001011
3202011222000120102020102
43010220111133231023
511424343302333120
6240554123120015
721153000263321
oct3045025375513
9664860512212
10211130121035
11815a34a3939
1234b0307300b
1316ba91a5402
14a30c383d11
15575a667d75
hex312855fb4b

211130121035 has 8 divisors (see below), whose sum is σ = 253421753760. Its totient is φ = 168860357824.

The previous prime is 211130121023. The next prime is 211130121061. The reversal of 211130121035 is 530121031112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 211130121035 - 214 = 211130104651 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211130120998 and 211130121016.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5446130 + ... + 5484759.

It is an arithmetic number, because the mean of its divisors is an integer number (31677719220).

Almost surely, 2211130121035 is an apocalyptic number.

211130121035 is a deficient number, since it is larger than the sum of its proper divisors (42291632725).

211130121035 is a wasteful number, since it uses less digits than its factorization.

211130121035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10934757.

The product of its (nonzero) digits is 180, while the sum is 20.

Adding to 211130121035 its reverse (530121031112), we get a palindrome (741251152147).

The spelling of 211130121035 in words is "two hundred eleven billion, one hundred thirty million, one hundred twenty-one thousand, thirty-five".

Divisors: 1 5 3863 19315 10930889 54654445 42226024207 211130121035