Base | Representation |
---|---|
bin | 1100010010100001010… |
… | …1011111101100111111 |
3 | 202011222000120102012222 |
4 | 3010220111133230333 |
5 | 11424343302333043 |
6 | 240554123115555 |
7 | 21153000263303 |
oct | 3045025375477 |
9 | 664860512188 |
10 | 211130121023 |
11 | 815a34a3928 |
12 | 34b03072bbb |
13 | 16ba91a53c3 |
14 | a30c383d03 |
15 | 575a667d68 |
hex | 312855fb3f |
211130121023 has 2 divisors, whose sum is σ = 211130121024. Its totient is φ = 211130121022.
The previous prime is 211130120963. The next prime is 211130121061. The reversal of 211130121023 is 320121031112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211130121023 - 222 = 211125926719 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211130120992 and 211130121010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211130171023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565060511 + 105565060512.
It is an arithmetic number, because the mean of its divisors is an integer number (105565060512).
Almost surely, 2211130121023 is an apocalyptic number.
211130121023 is a deficient number, since it is larger than the sum of its proper divisors (1).
211130121023 is an equidigital number, since it uses as much as digits as its factorization.
211130121023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 211130121023 its reverse (320121031112), we get a palindrome (531251152135).
The spelling of 211130121023 in words is "two hundred eleven billion, one hundred thirty million, one hundred twenty-one thousand, twenty-three".
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