Base | Representation |
---|---|
bin | 11110101110010011111… |
… | …000011111101101010111 |
3 | 21110211122211020212122221 |
4 | 132232103320133231113 |
5 | 234042430330044111 |
6 | 4253531124403211 |
7 | 305352141630235 |
oct | 36562370375527 |
9 | 7424584225587 |
10 | 2111310003031 |
11 | 744446500629 |
12 | 2a1229546507 |
13 | 12413228c2a8 |
14 | 7428ba39955 |
15 | 39dc00de371 |
hex | 1eb93e1fb57 |
2111310003031 has 2 divisors, whose sum is σ = 2111310003032. Its totient is φ = 2111310003030.
The previous prime is 2111310002993. The next prime is 2111310003041. The reversal of 2111310003031 is 1303000131112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111310003031 - 237 = 1973871049559 is a prime.
It is a super-2 number, since 2×21113100030312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2111310002996 and 2111310003014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111310003041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055655001515 + 1055655001516.
It is an arithmetic number, because the mean of its divisors is an integer number (1055655001516).
Almost surely, 22111310003031 is an apocalyptic number.
2111310003031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111310003031 is an equidigital number, since it uses as much as digits as its factorization.
2111310003031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 2111310003031 its reverse (1303000131112), we get a palindrome (3414310134143).
The spelling of 2111310003031 in words is "two trillion, one hundred eleven billion, three hundred ten million, three thousand, thirty-one".
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