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2111310003041 is a prime number
BaseRepresentation
bin11110101110010011111…
…000011111101101100001
321110211122211020212200022
4132232103320133231201
5234042430330044131
64253531124403225
7305352141630251
oct36562370375541
97424584225608
102111310003041
11744446500638
122a1229546515
1312413228c2b5
147428ba39961
1539dc00de37b
hex1eb93e1fb61

2111310003041 has 2 divisors, whose sum is σ = 2111310003042. Its totient is φ = 2111310003040.

The previous prime is 2111310003031. The next prime is 2111310003043. The reversal of 2111310003041 is 1403000131112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2025273380641 + 86036622400 = 1423121^2 + 293320^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111310003041 is a prime.

It is a super-3 number, since 3×21113100030413 (a number of 38 digits) contains 333 as substring.

Together with 2111310003043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2111310003043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055655001520 + 1055655001521.

It is an arithmetic number, because the mean of its divisors is an integer number (1055655001521).

Almost surely, 22111310003041 is an apocalyptic number.

It is an amenable number.

2111310003041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111310003041 is an equidigital number, since it uses as much as digits as its factorization.

2111310003041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 2111310003041 its reverse (1403000131112), we get a palindrome (3514310134153).

The spelling of 2111310003041 in words is "two trillion, one hundred eleven billion, three hundred ten million, three thousand, forty-one".