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2111310133 is a prime number
BaseRepresentation
bin111110111011000…
…0000100100110101
312110010210200000121
41331312000210311
513310443411013
6545300411541
7103214561062
oct17566004465
95403720017
102111310133
11993863609
124ab0a6bb1
1327854ab4a
14160591c69
15c554d58d
hex7dd80935

2111310133 has 2 divisors, whose sum is σ = 2111310134. Its totient is φ = 2111310132.

The previous prime is 2111310127. The next prime is 2111310137. The reversal of 2111310133 is 3310131112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1752510769 + 358799364 = 41863^2 + 18942^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111310133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111310137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055655066 + 1055655067.

It is an arithmetic number, because the mean of its divisors is an integer number (1055655067).

Almost surely, 22111310133 is an apocalyptic number.

It is an amenable number.

2111310133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111310133 is an equidigital number, since it uses as much as digits as its factorization.

2111310133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

The square root of 2111310133 is about 45948.9949073970. The cubic root of 2111310133 is about 1282.8740215781.

Adding to 2111310133 its reverse (3310131112), we get a palindrome (5421441245).

The spelling of 2111310133 in words is "two billion, one hundred eleven million, three hundred ten thousand, one hundred thirty-three".