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2111310127 is a prime number
BaseRepresentation
bin111110111011000…
…0000100100101111
312110010210200000101
41331312000210233
513310443411002
6545300411531
7103214561053
oct17566004457
95403720011
102111310127
11993863603
124ab0a6ba7
1327854ab44
14160591c63
15c554d587
hex7dd8092f

2111310127 has 2 divisors, whose sum is σ = 2111310128. Its totient is φ = 2111310126.

The previous prime is 2111310109. The next prime is 2111310133. The reversal of 2111310127 is 7210131112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2111310127 - 27 = 2111309999 is a prime.

It is a super-2 number, since 2×21113101272 = 8915260904745512258, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111310137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055655063 + 1055655064.

It is an arithmetic number, because the mean of its divisors is an integer number (1055655064).

Almost surely, 22111310127 is an apocalyptic number.

2111310127 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111310127 is an equidigital number, since it uses as much as digits as its factorization.

2111310127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

The square root of 2111310127 is about 45948.9948421073. The cubic root of 2111310127 is about 1282.8740203628.

Adding to 2111310127 its reverse (7210131112), we get a palindrome (9321441239).

The spelling of 2111310127 in words is "two billion, one hundred eleven million, three hundred ten thousand, one hundred twenty-seven".