Base | Representation |
---|---|
bin | 1100010010100001100… |
… | …1001110111111010111 |
3 | 202011222002102012200201 |
4 | 3010220121032333113 |
5 | 11424344030214033 |
6 | 240554200121331 |
7 | 21153011514634 |
oct | 3045031167727 |
9 | 664862365621 |
10 | 211131101143 |
11 | 815a4003246 |
12 | 34b03466247 |
13 | 16ba9459561 |
14 | a30c55b18b |
15 | 575a7ad47d |
hex | 312864efd7 |
211131101143 has 2 divisors, whose sum is σ = 211131101144. Its totient is φ = 211131101142.
The previous prime is 211131101117. The next prime is 211131101147. The reversal of 211131101143 is 341101131112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211131101143 - 237 = 73692147671 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 211131101143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211131101147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565550571 + 105565550572.
It is an arithmetic number, because the mean of its divisors is an integer number (105565550572).
Almost surely, 2211131101143 is an apocalyptic number.
211131101143 is a deficient number, since it is larger than the sum of its proper divisors (1).
211131101143 is an equidigital number, since it uses as much as digits as its factorization.
211131101143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 211131101143 its reverse (341101131112), we get a palindrome (552232232255).
The spelling of 211131101143 in words is "two hundred eleven billion, one hundred thirty-one million, one hundred one thousand, one hundred forty-three".
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