Base | Representation |
---|---|
bin | 1100010010100001100… |
… | …1010011100110000111 |
3 | 202011222002110011120101 |
4 | 3010220121103212013 |
5 | 11424344031320012 |
6 | 240554200344531 |
7 | 21153011623633 |
oct | 3045031234607 |
9 | 664862404511 |
10 | 211131120007 |
11 | 815a4016435 |
12 | 34b03475147 |
13 | 16ba9465012 |
14 | a30c563dc3 |
15 | 575a7b3d57 |
hex | 3128653987 |
211131120007 has 2 divisors, whose sum is σ = 211131120008. Its totient is φ = 211131120006.
The previous prime is 211131119929. The next prime is 211131120023. The reversal of 211131120007 is 700021131112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211131120007 - 27 = 211131119879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211131127007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565560003 + 105565560004.
It is an arithmetic number, because the mean of its divisors is an integer number (105565560004).
Almost surely, 2211131120007 is an apocalyptic number.
211131120007 is a deficient number, since it is larger than the sum of its proper divisors (1).
211131120007 is an equidigital number, since it uses as much as digits as its factorization.
211131120007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 211131120007 its reverse (700021131112), we get a palindrome (911152251119).
The spelling of 211131120007 in words is "two hundred eleven billion, one hundred thirty-one million, one hundred twenty thousand, seven".
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