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2111311981253 is a prime number
BaseRepresentation
bin11110101110010100000…
…000000010101011000101
321110211122221222101021102
4132232110000002223011
5234042431331400003
64253531235025445
7305352164506526
oct36562400025305
97424587871242
102111311981253
11744447631922
122a122a13b285
13124132802837
147428bdd284d
1539dc0380588
hex1eb94002ac5

2111311981253 has 2 divisors, whose sum is σ = 2111311981254. Its totient is φ = 2111311981252.

The previous prime is 2111311981211. The next prime is 2111311981271. The reversal of 2111311981253 is 3521891131112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1532688568324 + 578623412929 = 1238018^2 + 760673^2 .

It is a cyclic number.

It is not a de Polignac number, because 2111311981253 - 28 = 2111311980997 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111311921253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055655990626 + 1055655990627.

It is an arithmetic number, because the mean of its divisors is an integer number (1055655990627).

Almost surely, 22111311981253 is an apocalyptic number.

It is an amenable number.

2111311981253 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111311981253 is an equidigital number, since it uses as much as digits as its factorization.

2111311981253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12960, while the sum is 38.

The spelling of 2111311981253 in words is "two trillion, one hundred eleven billion, three hundred eleven million, nine hundred eighty-one thousand, two hundred fifty-three".