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21113120095 = 54222624019
BaseRepresentation
bin10011101010011100…
…001010010101011111
32000111102001121221221
4103222130022111133
5321214424320340
613411011234211
71345126362664
oct235234122537
960442047857
1021113120095
118a54895691
1241128a8967
131cb61a0392
14104407ba6b
1583884444a
hex4ea70a55f

21113120095 has 4 divisors (see below), whose sum is σ = 25335744120. Its totient is φ = 16890496072.

The previous prime is 21113120071. The next prime is 21113120111. The reversal of 21113120095 is 59002131112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21113120095 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2111312005 + ... + 2111312014.

It is an arithmetic number, because the mean of its divisors is an integer number (6333936030).

Almost surely, 221113120095 is an apocalyptic number.

21113120095 is a deficient number, since it is larger than the sum of its proper divisors (4222624025).

21113120095 is an equidigital number, since it uses as much as digits as its factorization.

21113120095 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4222624024.

The product of its (nonzero) digits is 540, while the sum is 25.

The spelling of 21113120095 in words is "twenty-one billion, one hundred thirteen million, one hundred twenty thousand, ninety-five".

Divisors: 1 5 4222624019 21113120095