211131211033 has 4 divisors (see below), whose sum is σ = 220310828928. Its totient is φ = 201951593140.

The previous prime is 211131211007. The next prime is 211131211097. The reversal of 211131211033 is 330112131112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211131211033 is a prime.

It is a super-2 number, since 2×211131211033² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 211131211033.

It is not an unprimeable number, because it can be changed into a prime (211131211433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4589808913 + ... + 4589808958.

It is an arithmetic number, because the mean of its divisors is an integer number (55077707232).

Almost surely, 2^211131211033 is an apocalyptic number.

211131211033 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

211131211033 is a deficient number, since it is larger than the sum of its proper divisors (9179617895).

211131211033 is an equidigital number, since it uses as much as digits as its factorization.

211131211033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9179617894.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 211131211033 its reverse (330112131112), we get a palindrome (541243342145).

The spelling of 211131211033 in words is "two hundred eleven billion, one hundred thirty-one million, two hundred eleven thousand, thirty-three".