211131211141 has 2 divisors, whose sum is σ = 211131211142. Its totient is φ = 211131211140.

The previous prime is 211131211129. The next prime is 211131211189. The reversal of 211131211141 is 141112131112.

It is a m-pointer prime, because the next prime (211131211189) can be obtained adding 211131211141 to its product of digits (48).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 173668060225 + 37463150916 = 416735^2 + 193554^2 .

It is a cyclic number.

It is not a de Polignac number, because 211131211141 - 2²⁷ = 210996993413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211131211441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565605570 + 105565605571.

It is an arithmetic number, because the mean of its divisors is an integer number (105565605571).

Almost surely, 2^211131211141 is an apocalyptic number.

It is an amenable number.

211131211141 is a deficient number, since it is larger than the sum of its proper divisors (1).

211131211141 is an equidigital number, since it uses as much as digits as its factorization.

211131211141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 19.

Adding to 211131211141 its reverse (141112131112), we get a palindrome (352243342253).

The spelling of 211131211141 in words is "two hundred eleven billion, one hundred thirty-one million, two hundred eleven thousand, one hundred forty-one".