2111312220013 has 4 divisors (see below), whose sum is σ = 2111372101440. Its totient is φ = 2111252338588.

The previous prime is 2111312219941. The next prime is 2111312220047. The reversal of 2111312220013 is 3100222131112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2111312220013 - 2⁹ = 2111312219501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111312280013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29887795 + ... + 29958352.

It is an arithmetic number, because the mean of its divisors is an integer number (527843025360).

Almost surely, 2^{2111312220013} is an apocalyptic number.

It is an amenable number.

2111312220013 is a deficient number, since it is larger than the sum of its proper divisors (59881427).

2111312220013 is an equidigital number, since it uses as much as digits as its factorization.

2111312220013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59881426.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2111312220013 its reverse (3100222131112), we get a palindrome (5211534351125).

The spelling of 2111312220013 in words is "two trillion, one hundred eleven billion, three hundred twelve million, two hundred twenty thousand, thirteen".