Base | Representation |
---|---|
bin | 11110101110010100000… |
… | …001101011111010001101 |
3 | 21110211122222210021120011 |
4 | 132232110001223322031 |
5 | 234042431434143201 |
6 | 4253531252153221 |
7 | 305352201253321 |
oct | 36562401537215 |
9 | 7424588707504 |
10 | 2111312412301 |
11 | 7444478a6764 |
12 | 2a122a308811 |
13 | 124132923ab1 |
14 | 7428c0a5981 |
15 | 39dc0418151 |
hex | 1eb9406be8d |
2111312412301 has 2 divisors, whose sum is σ = 2111312412302. Its totient is φ = 2111312412300.
The previous prime is 2111312412283. The next prime is 2111312412317. The reversal of 2111312412301 is 1032142131112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1454930502025 + 656381910276 = 1206205^2 + 810174^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111312412301 - 27 = 2111312412173 is a prime.
It is a super-2 number, since 2×21113124123012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2111312412361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055656206150 + 1055656206151.
It is an arithmetic number, because the mean of its divisors is an integer number (1055656206151).
Almost surely, 22111312412301 is an apocalyptic number.
It is an amenable number.
2111312412301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111312412301 is an equidigital number, since it uses as much as digits as its factorization.
2111312412301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 2111312412301 its reverse (1032142131112), we get a palindrome (3143454543413).
The spelling of 2111312412301 in words is "two trillion, one hundred eleven billion, three hundred twelve million, four hundred twelve thousand, three hundred one".
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