21113124132 has 12 divisors (see below), whose sum is σ = 49263956336. Its totient is φ = 7037708040.

The previous prime is 21113124107. The next prime is 21113124139. The reversal of 21113124132 is 23142131112.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×21113124132² (a number of 21 digits) contains 22 as substring.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 21113124099 and 21113124108.

It is not an unprimeable number, because it can be changed into a prime (21113124139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 879713494 + ... + 879713517.

Almost surely, 2^21113124132 is an apocalyptic number.

It is an amenable number.

21113124132 is an abundant number, since it is smaller than the sum of its proper divisors (28150832204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21113124132 is a wasteful number, since it uses less digits than its factorization.

21113124132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1759427018 (or 1759427016 counting only the distinct ones).

The product of its digits is 288, while the sum is 21.

Adding to 21113124132 its reverse (23142131112), we get a palindrome (44255255244).

The spelling of 21113124132 in words is "twenty-one billion, one hundred thirteen million, one hundred twenty-four thousand, one hundred thirty-two".