Base | Representation |
---|---|
bin | 1100010010100001110… |
… | …0101010111011100111 |
3 | 202011222011002222110122 |
4 | 3010220130222323213 |
5 | 11424344243031043 |
6 | 240554231312155 |
7 | 21153022256255 |
oct | 3045034527347 |
9 | 664864088418 |
10 | 211132002023 |
11 | 815a4569078 |
12 | 34b0381b65b |
13 | 16ba96b3617 |
14 | a30c7135d5 |
15 | 575a8da368 |
hex | 312872aee7 |
211132002023 has 4 divisors (see below), whose sum is σ = 211133519688. Its totient is φ = 211130484360.
The previous prime is 211132002019. The next prime is 211132002041. The reversal of 211132002023 is 320200231112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211132002023 - 22 = 211132002019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 211132001992 and 211132002010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211132062023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 526433 + ... + 836298.
It is an arithmetic number, because the mean of its divisors is an integer number (52783379922).
Almost surely, 2211132002023 is an apocalyptic number.
211132002023 is a deficient number, since it is larger than the sum of its proper divisors (1517665).
211132002023 is a wasteful number, since it uses less digits than its factorization.
211132002023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1517664.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 211132002023 its reverse (320200231112), we get a palindrome (531332233135).
The spelling of 211132002023 in words is "two hundred eleven billion, one hundred thirty-two million, two thousand, twenty-three".
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