2111320023 has 4 divisors (see below), whose sum is σ = 2815093368. Its totient is φ = 1407546680.

The previous prime is 2111320019. The next prime is 2111320037. The reversal of 2111320023 is 3200231112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2111320023 - 2² = 2111320019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2111319984 and 2111320011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111320063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351886668 + ... + 351886673.

It is an arithmetic number, because the mean of its divisors is an integer number (703773342).

Almost surely, 2^2111320023 is an apocalyptic number.

2111320023 is a deficient number, since it is larger than the sum of its proper divisors (703773345).

2111320023 is an equidigital number, since it uses as much as digits as its factorization.

2111320023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 703773344.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 2111320023 is about 45949.1025266000. The cubic root of 2111320023 is about 1282.8760246952.

Adding to 2111320023 its reverse (3200231112), we get a palindrome (5311551135).

The spelling of 2111320023 in words is "two billion, one hundred eleven million, three hundred twenty thousand, twenty-three".