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21113201210117 is a prime number
BaseRepresentation
bin1001100110011110011001…
…10110111011001100000101
32202202101212021221020020112
410303033030312323030011
510231404314002210432
6112523134251242405
74306243544131322
oct463171466731405
982671767836215
1021113201210117
116800070732635
12244ba68449405
13ba1c7404ca33
1452dc54aa9b49
152693097817b2
hex1333ccdbb305

21113201210117 has 2 divisors, whose sum is σ = 21113201210118. Its totient is φ = 21113201210116.

The previous prime is 21113201210041. The next prime is 21113201210141. The reversal of 21113201210117 is 71101210231112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16857256966081 + 4255944244036 = 4105759^2 + 2062994^2 .

It is a cyclic number.

It is not a de Polignac number, because 21113201210117 - 238 = 20838323303173 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21113201210092 and 21113201210101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21113201210177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556600605058 + 10556600605059.

It is an arithmetic number, because the mean of its divisors is an integer number (10556600605059).

Almost surely, 221113201210117 is an apocalyptic number.

It is an amenable number.

21113201210117 is a deficient number, since it is larger than the sum of its proper divisors (1).

21113201210117 is an equidigital number, since it uses as much as digits as its factorization.

21113201210117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 23.

Adding to 21113201210117 its reverse (71101210231112), we get a palindrome (92214411441229).

The spelling of 21113201210117 in words is "twenty-one trillion, one hundred thirteen billion, two hundred one million, two hundred ten thousand, one hundred seventeen".