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21113344303 = 98453214451
BaseRepresentation
bin10011101010011101…
…000001000100101111
32000111102111000111221
4103222131001010233
5321220004004203
613411020124211
71345131315442
oct235235010457
960442430457
1021113344303
118a54a29087
124112996667
131cb624b44c
1410440d9659
1583888aabd
hex4ea74112f

21113344303 has 4 divisors (see below), whose sum is σ = 21113657208. Its totient is φ = 21113031400.

The previous prime is 21113344267. The next prime is 21113344319. The reversal of 21113344303 is 30344331112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21113344303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21113344333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8773 + ... + 205678.

It is an arithmetic number, because the mean of its divisors is an integer number (5278414302).

Almost surely, 221113344303 is an apocalyptic number.

21113344303 is a deficient number, since it is larger than the sum of its proper divisors (312905).

21113344303 is an equidigital number, since it uses as much as digits as its factorization.

21113344303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312904.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 21113344303 its reverse (30344331112), we get a palindrome (51457675415).

The spelling of 21113344303 in words is "twenty-one billion, one hundred thirteen million, three hundred forty-four thousand, three hundred three".

Divisors: 1 98453 214451 21113344303