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2111420141 = 13116117711
BaseRepresentation
bin111110111011001…
…1011011011101101
312110011000020220222
41331312123123231
513311010421031
6545303021125
7103215526565
oct17566333355
95404006828
102111420141
11993929226
124ab13a7a5
13278588c3c
141605bdda5
15c5570e7b
hex7dd9b6ed

2111420141 has 4 divisors (see below), whose sum is σ = 2127537984. Its totient is φ = 2095302300.

The previous prime is 2111420131. The next prime is 2111420159. The reversal of 2111420141 is 1410241112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111420141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111420131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8058725 + ... + 8058986.

It is an arithmetic number, because the mean of its divisors is an integer number (531884496).

Almost surely, 22111420141 is an apocalyptic number.

It is an amenable number.

2111420141 is a deficient number, since it is larger than the sum of its proper divisors (16117843).

2111420141 is a wasteful number, since it uses less digits than its factorization.

2111420141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16117842.

The product of its (nonzero) digits is 64, while the sum is 17.

The square root of 2111420141 is about 45950.1919582498. The cubic root of 2111420141 is about 1282.8963022072.

Adding to 2111420141 its reverse (1410241112), we get a palindrome (3521661253).

The spelling of 2111420141 in words is "two billion, one hundred eleven million, four hundred twenty thousand, one hundred forty-one".

Divisors: 1 131 16117711 2111420141