Base | Representation |
---|---|
bin | 11110101110111101000… |
… | …100011100011000010101 |
3 | 21110220102222111012122121 |
4 | 132232331010130120111 |
5 | 234100334224012411 |
6 | 4254123451055541 |
7 | 305405232206434 |
oct | 36567504343025 |
9 | 7426388435577 |
10 | 2112001000981 |
11 | 744770561613 |
12 | 2a13a0a415b1 |
13 | 124212499111 |
14 | 7431570d11b |
15 | 39e10ad4571 |
hex | 1ebbd11c615 |
2112001000981 has 2 divisors, whose sum is σ = 2112001000982. Its totient is φ = 2112001000980.
The previous prime is 2112001000951. The next prime is 2112001001003. The reversal of 2112001000981 is 1890001002112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1790096823025 + 321904177956 = 1337945^2 + 567366^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112001000981 - 225 = 2111967446549 is a prime.
It is a super-2 number, since 2×21120010009812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112001000951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056000500490 + 1056000500491.
It is an arithmetic number, because the mean of its divisors is an integer number (1056000500491).
Almost surely, 22112001000981 is an apocalyptic number.
It is an amenable number.
2112001000981 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112001000981 is an equidigital number, since it uses as much as digits as its factorization.
2112001000981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 25.
The spelling of 2112001000981 in words is "two trillion, one hundred twelve billion, one million, nine hundred eighty-one", and thus it is an aban number.
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