Base | Representation |
---|---|
bin | 1001100110101011011110… |
… | …01101011110111101101111 |
3 | 2202210001222110000201001111 |
4 | 10303111233031132331233 |
5 | 10232013202310000421 |
6 | 112530254540252451 |
7 | 4306612511640031 |
oct | 463255715367557 |
9 | 82701873021044 |
10 | 21120220000111 |
11 | 6803042650421 |
12 | 24512a6b41127 |
13 | ba28222043cb |
14 | 53031cd17c51 |
15 | 2695baa5cee1 |
hex | 13356f35ef6f |
21120220000111 has 2 divisors, whose sum is σ = 21120220000112. Its totient is φ = 21120220000110.
The previous prime is 21120220000081. The next prime is 21120220000169. The reversal of 21120220000111 is 11100002202112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21120220000111 - 25 = 21120220000079 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21120220000091 and 21120220000100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21120220000181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560110000055 + 10560110000056.
It is an arithmetic number, because the mean of its divisors is an integer number (10560110000056).
Almost surely, 221120220000111 is an apocalyptic number.
21120220000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
21120220000111 is an equidigital number, since it uses as much as digits as its factorization.
21120220000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 21120220000111 its reverse (11100002202112), we get a palindrome (32220222202223).
The spelling of 21120220000111 in words is "twenty-one trillion, one hundred twenty billion, two hundred twenty million, one hundred eleven", and thus it is an aban number.
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