Base | Representation |
---|---|
bin | 1001100110101101000001… |
… | …10000110011100110010111 |
3 | 2202210011010101100022110022 |
4 | 10303112200300303212113 |
5 | 10232021403120441010 |
6 | 112530513235015355 |
7 | 4306642225145003 |
oct | 463264060634627 |
9 | 82704111308408 |
10 | 21121051343255 |
11 | 6803429949876 |
12 | 245149943a55b |
13 | ba292550c726 |
14 | 53039b4c1703 |
15 | 269618a26d55 |
hex | 1335a0c33997 |
21121051343255 has 4 divisors (see below), whose sum is σ = 25345261611912. Its totient is φ = 16896841074600.
The previous prime is 21121051343233. The next prime is 21121051343333. The reversal of 21121051343255 is 55234315012112.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 21121051343255 - 222 = 21121047148951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2112105134321 + ... + 2112105134330.
It is an arithmetic number, because the mean of its divisors is an integer number (6336315402978).
Almost surely, 221121051343255 is an apocalyptic number.
21121051343255 is a deficient number, since it is larger than the sum of its proper divisors (4224210268657).
21121051343255 is an equidigital number, since it uses as much as digits as its factorization.
21121051343255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4224210268656.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 21121051343255 its reverse (55234315012112), we get a palindrome (76355366355367).
The spelling of 21121051343255 in words is "twenty-one trillion, one hundred twenty-one billion, fifty-one million, three hundred forty-three thousand, two hundred fifty-five".
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