Base | Representation |
---|---|
bin | 11110101111000011100… |
… | …100010000011100110111 |
3 | 21110220201120121010201022 |
4 | 132233003210100130313 |
5 | 234101100130112043 |
6 | 4254142343251355 |
7 | 305411024546525 |
oct | 36570344203467 |
9 | 7426646533638 |
10 | 2112110004023 |
11 | 744817042178 |
12 | 2a1411449b5b |
13 | 12422bc42766 |
14 | 74325da5315 |
15 | 39e1a466868 |
hex | 1ebc3910737 |
2112110004023 has 2 divisors, whose sum is σ = 2112110004024. Its totient is φ = 2112110004022.
The previous prime is 2112110004019. The next prime is 2112110004041. The reversal of 2112110004023 is 3204000112112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2112110004023 - 22 = 2112110004019 is a prime.
It is a super-2 number, since 2×21121100040232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112110003992 and 2112110004010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112110004523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056055002011 + 1056055002012.
It is an arithmetic number, because the mean of its divisors is an integer number (1056055002012).
Almost surely, 22112110004023 is an apocalyptic number.
2112110004023 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112110004023 is an equidigital number, since it uses as much as digits as its factorization.
2112110004023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2112110004023 its reverse (3204000112112), we get a palindrome (5316110116135).
The spelling of 2112110004023 in words is "two trillion, one hundred twelve billion, one hundred ten million, four thousand, twenty-three".
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