Base | Representation |
---|---|
bin | 1100010010110100101… |
… | …0011001111111110111 |
3 | 202012011122221120200221 |
4 | 3010231022121333313 |
5 | 11430030020201101 |
6 | 241010134515211 |
7 | 21155002505122 |
oct | 3045512317767 |
9 | 665148846627 |
10 | 211211100151 |
11 | 81635183727 |
12 | 34b26205b07 |
13 | 16bbcbb934c |
14 | a3190233b9 |
15 | 5762811aa1 |
hex | 312d299ff7 |
211211100151 has 2 divisors, whose sum is σ = 211211100152. Its totient is φ = 211211100150.
The previous prime is 211211100101. The next prime is 211211100161. The reversal of 211211100151 is 151001112112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211211100151 - 29 = 211211099639 is a prime.
It is a super-2 number, since 2×2112111001512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211211100101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605550075 + 105605550076.
It is an arithmetic number, because the mean of its divisors is an integer number (105605550076).
Almost surely, 2211211100151 is an apocalyptic number.
211211100151 is a deficient number, since it is larger than the sum of its proper divisors (1).
211211100151 is an equidigital number, since it uses as much as digits as its factorization.
211211100151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20, while the sum is 16.
Adding to 211211100151 its reverse (151001112112), we get a palindrome (362212212263).
The spelling of 211211100151 in words is "two hundred eleven billion, two hundred eleven million, one hundred thousand, one hundred fifty-one".
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