Base | Representation |
---|---|
bin | 1100010010110100101… |
… | …0011010010010010101 |
3 | 202012011122221122022201 |
4 | 3010231022122102111 |
5 | 11430030020220313 |
6 | 241010134524501 |
7 | 21155002511431 |
oct | 3045512322225 |
9 | 665148848281 |
10 | 211211101333 |
11 | 81635184601 |
12 | 34b26206731 |
13 | 16bbcbb9a4b |
14 | a3190239c1 |
15 | 57628120dd |
hex | 312d29a495 |
211211101333 has 4 divisors (see below), whose sum is σ = 211243497228. Its totient is φ = 211178705440.
The previous prime is 211211101319. The next prime is 211211101337. The reversal of 211211101333 is 333101112112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 198026780004 + 13184321329 = 445002^2 + 114823^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211211101333 is a prime.
It is a super-2 number, since 2×2112111013332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 211211101333.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211211101337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16188166 + ... + 16201207.
It is an arithmetic number, because the mean of its divisors is an integer number (52810874307).
Almost surely, 2211211101333 is an apocalyptic number.
It is an amenable number.
211211101333 is a deficient number, since it is larger than the sum of its proper divisors (32395895).
211211101333 is an equidigital number, since it uses as much as digits as its factorization.
211211101333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32395894.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 211211101333 its reverse (333101112112), we get a palindrome (544312213445).
The spelling of 211211101333 in words is "two hundred eleven billion, two hundred eleven million, one hundred one thousand, three hundred thirty-three".
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