211211130112013 has 4 divisors (see below), whose sum is σ = 216123016858848. Its totient is φ = 206299243365180.

The previous prime is 211211130111977. The next prime is 211211130112079. The reversal of 211211130112013 is 310211031112112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211211130112013 is a prime.

It is a super-2 number, since 2×211211130112013² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211211130112613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2455943373353 + ... + 2455943373438.

It is an arithmetic number, because the mean of its divisors is an integer number (54030754214712).

Almost surely, 2^{211211130112013} is an apocalyptic number.

It is an amenable number.

211211130112013 is a deficient number, since it is larger than the sum of its proper divisors (4911886746835).

211211130112013 is an equidigital number, since it uses as much as digits as its factorization.

211211130112013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4911886746834.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 211211130112013 its reverse (310211031112112), we get a palindrome (521422161224125).

The spelling of 211211130112013 in words is "two hundred eleven trillion, two hundred eleven billion, one hundred thirty million, one hundred twelve thousand, thirteen".