211211220033 has 96 divisors (see below), whose sum is σ = 352898582400. Its totient is φ = 124710727680.

The previous prime is 211211220001. The next prime is 211211220079. The reversal of 211211220033 is 330022112112.

It is not a de Polignac number, because 211211220033 - 2⁵ = 211211220001 is a prime.

It is a super-3 number, since 3×211211220033³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 211211219988 and 211211220015.

It is not an unprimeable number, because it can be changed into a prime (211211240033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 21776241 + ... + 21785937.

It is an arithmetic number, because the mean of its divisors is an integer number (3676026900).

Almost surely, 2^211211220033 is an apocalyptic number.

It is an amenable number.

211211220033 is a deficient number, since it is larger than the sum of its proper divisors (141687362367).

211211220033 is a wasteful number, since it uses less digits than its factorization.

211211220033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9900 (or 9883 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 211211220033 its reverse (330022112112), we get a palindrome (541233332145).

The spelling of 211211220033 in words is "two hundred eleven billion, two hundred eleven million, two hundred twenty thousand, thirty-three".