211211313101 has 4 divisors (see below), whose sum is σ = 212507088192. Its totient is φ = 209915538012.

The previous prime is 211211313097. The next prime is 211211313109. The reversal of 211211313101 is 101313112112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211211313101 - 2² = 211211313097 is a prime.

It is a super-2 number, since 2×211211313101² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 211211313101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211211313109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 647887301 + ... + 647887626.

It is an arithmetic number, because the mean of its divisors is an integer number (53126772048).

Almost surely, 2^211211313101 is an apocalyptic number.

It is an amenable number.

211211313101 is a deficient number, since it is larger than the sum of its proper divisors (1295775091).

211211313101 is a wasteful number, since it uses less digits than its factorization.

211211313101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1295775090.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 211211313101 its reverse (101313112112), we get a palindrome (312524425213).

The spelling of 211211313101 in words is "two hundred eleven billion, two hundred eleven million, three hundred thirteen thousand, one hundred one".