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211212132011 = 316813294581
BaseRepresentation
bin1100010010110100111…
…0010101111010101011
3202012011201220000010222
43010231032111322223
511430030301211021
6241010213000255
721155014333346
oct3045516257253
9665151800128
10211212132011
1181635818a01
1234b2662308b
1316bc018ac0a
14a31921145d
1557629676ab
hex312d395eab

211212132011 has 4 divisors (see below), whose sum is σ = 218025426624. Its totient is φ = 204398837400.

The previous prime is 211212132007. The next prime is 211212132029. The reversal of 211212132011 is 110231212112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211212132011 - 22 = 211212132007 is a prime.

It is a super-2 number, since 2×2112121320112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211212132041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3406647260 + ... + 3406647321.

It is an arithmetic number, because the mean of its divisors is an integer number (54506356656).

Almost surely, 2211212132011 is an apocalyptic number.

211212132011 is a deficient number, since it is larger than the sum of its proper divisors (6813294613).

211212132011 is an equidigital number, since it uses as much as digits as its factorization.

211212132011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6813294612.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 211212132011 its reverse (110231212112), we get a palindrome (321443344123).

The spelling of 211212132011 in words is "two hundred eleven billion, two hundred twelve million, one hundred thirty-two thousand, eleven".

Divisors: 1 31 6813294581 211212132011