| Base | Representation |
|---|---|
| bin | 1001100110101101011111… |
| … | …00110001101010001111100 |
| 3 | 2202210011202201122201102100 |
| 4 | 10303112233212031101330 |
| 5 | 10232022410324114400 |
| 6 | 112530554045225100 |
| 7 | 4306651336453140 |
| oct | 463265746152174 |
| 9 | 82704681581370 |
| 10 | 21121300223100 |
| 11 | 68035473879a0 |
| 12 | 2451548862190 |
| 13 | ba2964c4c2cc |
| 14 | 5303c2589220 |
| 15 | 2696307d9100 |
| hex | 1335af98d47c |
21121300223100 has 432 divisors, whose sum is σ = 82652284915200. Its totient is φ = 4382843558400.
The previous prime is 21121300222999. The next prime is 21121300223131. The reversal of 21121300223100 is 132200312112.
21121300223100 is a `hidden beast` number, since 2 + 11 + 21 + 300 + 22 + 310 + 0 = 666.
It is a super-2 number, since 2×211213002231002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 50589001 + ... + 51004799.
It is an arithmetic number, because the mean of its divisors is an integer number (191324733600).
Almost surely, 221121300223100 is an apocalyptic number.
21121300223100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 21121300223100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (41326142457600).
21121300223100 is an abundant number, since it is smaller than the sum of its proper divisors (61530984692100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21121300223100 is a wasteful number, since it uses less digits than its factorization.
21121300223100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 416570 (or 416560 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 21121300223100 its reverse (132200312112), we get a palindrome (21253500535212).
It can be divided in two parts, 21121300 and 223100, that added together give a square (21344400 = 46202).
The spelling of 21121300223100 in words is "twenty-one trillion, one hundred twenty-one billion, three hundred million, two hundred twenty-three thousand, one hundred".
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