211213102203133 has 2 divisors, whose sum is σ = 211213102203134. Its totient is φ = 211213102203132.

The previous prime is 211213102203127. The next prime is 211213102203197. The reversal of 211213102203133 is 331302201312112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 207398104150329 + 3814998052804 = 14401323^2 + 1953202^2 .

It is a cyclic number.

It is not a de Polignac number, because 211213102203133 - 2⁵ = 211213102203101 is a prime.

It is a super-2 number, since 2×211213102203133² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211213102203098 and 211213102203107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211213102204133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606551101566 + 105606551101567.

It is an arithmetic number, because the mean of its divisors is an integer number (105606551101567).

Almost surely, 2^{211213102203133} is an apocalyptic number.

It is an amenable number.

211213102203133 is a deficient number, since it is larger than the sum of its proper divisors (1).

211213102203133 is an equidigital number, since it uses as much as digits as its factorization.

211213102203133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 211213102203133 its reverse (331302201312112), we get a palindrome (542515303515245).

The spelling of 211213102203133 in words is "two hundred eleven trillion, two hundred thirteen billion, one hundred two million, two hundred three thousand, one hundred thirty-three".