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21121320014 = 210560660007
BaseRepresentation
bin10011101010111011…
…011100010001001110
32000111222111020010122
4103222323130101032
5321224024220024
613411503104542
71345256154314
oct235273342116
960458436118
1021121320014
118a59486383
1241155a2152
131cb7ab17c2
1410451b40b4
15839413d5e
hex4eaedc44e

21121320014 has 4 divisors (see below), whose sum is σ = 31681980024. Its totient is φ = 10560660006.

The previous prime is 21121320001. The next prime is 21121320071. The reversal of 21121320014 is 41002312112.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×211213200142 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21121319974 and 21121320001.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5280330002 + ... + 5280330005.

It is an arithmetic number, because the mean of its divisors is an integer number (7920495006).

Almost surely, 221121320014 is an apocalyptic number.

21121320014 is a deficient number, since it is larger than the sum of its proper divisors (10560660010).

21121320014 is a wasteful number, since it uses less digits than its factorization.

21121320014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10560660009.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 21121320014 its reverse (41002312112), we get a palindrome (62123632126).

The spelling of 21121320014 in words is "twenty-one billion, one hundred twenty-one million, three hundred twenty thousand, fourteen".

Divisors: 1 2 10560660007 21121320014