Base | Representation |
---|---|
bin | 1100010010110101001… |
… | …1001110011100010011 |
3 | 202012011211022001010020 |
4 | 3010231103032130103 |
5 | 11430031113141430 |
6 | 241010300234523 |
7 | 21155031244416 |
oct | 3045523163423 |
9 | 665154261106 |
10 | 211213412115 |
11 | 81636512742 |
12 | 34b26b3ba43 |
13 | 16bc0518784 |
14 | a319465b7d |
15 | 5762b1bb10 |
hex | 312d4ce713 |
211213412115 has 16 divisors (see below), whose sum is σ = 342013045248. Its totient is φ = 111289957856.
The previous prime is 211213412083. The next prime is 211213412141. The reversal of 211213412115 is 511214312112.
It is a happy number.
211213412115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 211213412115 - 25 = 211213412083 is a prime.
It is a super-2 number, since 2×2112134121152 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 84823419 + ... + 84825908.
It is an arithmetic number, because the mean of its divisors is an integer number (21375815328).
Almost surely, 2211213412115 is an apocalyptic number.
211213412115 is a deficient number, since it is larger than the sum of its proper divisors (130799633133).
211213412115 is a wasteful number, since it uses less digits than its factorization.
211213412115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 169649418.
The product of its digits is 480, while the sum is 24.
Adding to 211213412115 its reverse (511214312112), we get a palindrome (722427724227).
The spelling of 211213412115 in words is "two hundred eleven billion, two hundred thirteen million, four hundred twelve thousand, one hundred fifteen".
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