Base | Representation |
---|---|
bin | 1100010010110101001… |
… | …1001110011100101101 |
3 | 202012011211022001011012 |
4 | 3010231103032130231 |
5 | 11430031113142031 |
6 | 241010300235005 |
7 | 21155031244454 |
oct | 3045523163455 |
9 | 665154261135 |
10 | 211213412141 |
11 | 81636512766 |
12 | 34b26b3ba65 |
13 | 16bc05187a4 |
14 | a319465b9b |
15 | 5762b1bb2b |
hex | 312d4ce72d |
211213412141 has 2 divisors, whose sum is σ = 211213412142. Its totient is φ = 211213412140.
The previous prime is 211213412083. The next prime is 211213412147. The reversal of 211213412141 is 141214312112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 208898358916 + 2315053225 = 457054^2 + 48115^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211213412141 is a prime.
It is a super-2 number, since 2×2112134121412 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211213412147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606706070 + 105606706071.
It is an arithmetic number, because the mean of its divisors is an integer number (105606706071).
Almost surely, 2211213412141 is an apocalyptic number.
It is an amenable number.
211213412141 is a deficient number, since it is larger than the sum of its proper divisors (1).
211213412141 is an equidigital number, since it uses as much as digits as its factorization.
211213412141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 384, while the sum is 23.
Adding to 211213412141 its reverse (141214312112), we get a palindrome (352427724253).
The spelling of 211213412141 in words is "two hundred eleven billion, two hundred thirteen million, four hundred twelve thousand, one hundred forty-one".
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