Base | Representation |
---|---|
bin | 111110111100100… |
… | …1110011101011101 |
3 | 12110012101111211002 |
4 | 1331321032131131 |
5 | 13311202402222 |
6 | 545330440045 |
7 | 103225002512 |
oct | 17571163535 |
9 | 5405344732 |
10 | 2112153437 |
11 | 99428a159 |
12 | 4ab433025 |
13 | 278784944 |
14 | 160731309 |
15 | c5668392 |
hex | 7de4e75d |
2112153437 has 2 divisors, whose sum is σ = 2112153438. Its totient is φ = 2112153436.
The previous prime is 2112153431. The next prime is 2112153497. The reversal of 2112153437 is 7343512112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2092696516 + 19456921 = 45746^2 + 4411^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112153437 is a prime.
It is a super-2 number, since 2×21121534372 = 8922384282861825938, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112153431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056076718 + 1056076719.
It is an arithmetic number, because the mean of its divisors is an integer number (1056076719).
Almost surely, 22112153437 is an apocalyptic number.
It is an amenable number.
2112153437 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112153437 is an equidigital number, since it uses as much as digits as its factorization.
2112153437 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5040, while the sum is 29.
The square root of 2112153437 is about 45958.1705140664. The cubic root of 2112153437 is about 1283.0448016023.
Adding to 2112153437 its reverse (7343512112), we get a palindrome (9455665549).
The spelling of 2112153437 in words is "two billion, one hundred twelve million, one hundred fifty-three thousand, four hundred thirty-seven".
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