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2112153431 is a prime number
BaseRepresentation
bin111110111100100…
…1110011101010111
312110012101111210212
41331321032131113
513311202402211
6545330440035
7103225002503
oct17571163527
95405344725
102112153431
1199428a153
124ab43301b
1327878493b
14160731303
15c566838b
hex7de4e757

2112153431 has 2 divisors, whose sum is σ = 2112153432. Its totient is φ = 2112153430.

The previous prime is 2112153409. The next prime is 2112153437. The reversal of 2112153431 is 1343512112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2112153431 - 226 = 2045044567 is a prime.

It is a super-2 number, since 2×21121534312 = 8922384232170143522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2112153397 and 2112153406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112153437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056076715 + 1056076716.

It is an arithmetic number, because the mean of its divisors is an integer number (1056076716).

Almost surely, 22112153431 is an apocalyptic number.

2112153431 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112153431 is an equidigital number, since it uses as much as digits as its factorization.

2112153431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 720, while the sum is 23.

The square root of 2112153431 is about 45958.1704487896. The cubic root of 2112153431 is about 1283.0448003874.

Adding to 2112153431 its reverse (1343512112), we get a palindrome (3455665543).

The spelling of 2112153431 in words is "two billion, one hundred twelve million, one hundred fifty-three thousand, four hundred thirty-one".