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211220220173 is a prime number
BaseRepresentation
bin1100010010110110110…
…1001100100100001101
3202012012022002221000112
43010231231030210031
511430034334021143
6241011102205405
721155143151114
oct3045555144415
9665168087015
10211220220173
118163a342736
1234b29283865
1316bc1a60501
14a31a318c7b
155763513e18
hex312db4c90d

211220220173 has 2 divisors, whose sum is σ = 211220220174. Its totient is φ = 211220220172.

The previous prime is 211220220137. The next prime is 211220220179. The reversal of 211220220173 is 371022022112.

Together with previous prime (211220220137) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 211220210569 + 9604 = 459587^2 + 98^2 .

It is a cyclic number.

It is not a de Polignac number, because 211220220173 - 234 = 194040350989 is a prime.

It is a super-2 number, since 2×2112202201732 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211220220179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610110086 + 105610110087.

It is an arithmetic number, because the mean of its divisors is an integer number (105610110087).

Almost surely, 2211220220173 is an apocalyptic number.

It is an amenable number.

211220220173 is a deficient number, since it is larger than the sum of its proper divisors (1).

211220220173 is an equidigital number, since it uses as much as digits as its factorization.

211220220173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 23.

Adding to 211220220173 its reverse (371022022112), we get a palindrome (582242242285).

The spelling of 211220220173 in words is "two hundred eleven billion, two hundred twenty million, two hundred twenty thousand, one hundred seventy-three".