Search a number
-
+
211220301113 is a prime number
BaseRepresentation
bin1100010010110110110…
…1100000010100111001
3202012012022021001001022
43010231231200110321
511430034344113423
6241011104032225
721155143636103
oct3045555402471
9665168231038
10211220301113
118163a398528
1234b29302675
1316bc1a8b2c3
14a31a33a573
15576352cdc8
hex312db60539

211220301113 has 2 divisors, whose sum is σ = 211220301114. Its totient is φ = 211220301112.

The previous prime is 211220300999. The next prime is 211220301137. The reversal of 211220301113 is 311103022112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 206763002944 + 4457298169 = 454712^2 + 66763^2 .

It is a cyclic number.

It is not a de Polignac number, because 211220301113 - 210 = 211220300089 is a prime.

It is a super-2 number, since 2×2112203011132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211220301091 and 211220301100.

It is not a weakly prime, because it can be changed into another prime (211220361113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610150556 + 105610150557.

It is an arithmetic number, because the mean of its divisors is an integer number (105610150557).

Almost surely, 2211220301113 is an apocalyptic number.

It is an amenable number.

211220301113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211220301113 is an equidigital number, since it uses as much as digits as its factorization.

211220301113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 211220301113 its reverse (311103022112), we get a palindrome (522323323225).

The spelling of 211220301113 in words is "two hundred eleven billion, two hundred twenty million, three hundred one thousand, one hundred thirteen".