Base | Representation |
---|---|
bin | 11110101111001001100… |
… | …101111101010010001111 |
3 | 21110220222121212000022001 |
4 | 132233021211331102033 |
5 | 234101302021104403 |
6 | 4254200354333131 |
7 | 305413363141300 |
oct | 36571145752217 |
9 | 7426877760261 |
10 | 2112211113103 |
11 | 7448691209a3 |
12 | 2a143b28a1a7 |
13 | 124246b84010 |
14 | 743355a47a7 |
15 | 39e24289c1d |
hex | 1ebc997d48f |
2112211113103 has 48 divisors (see below), whose sum is σ = 2654902014240. Its totient is φ = 1665629650944.
The previous prime is 2112211113083. The next prime is 2112211113109. The reversal of 2112211113103 is 3013111122112.
It is not a de Polignac number, because 2112211113103 - 213 = 2112211104911 is a prime.
It is a super-2 number, since 2×21122111131032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112211113109) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 247356208 + ... + 247364746.
It is an arithmetic number, because the mean of its divisors is an integer number (55310458630).
Almost surely, 22112211113103 is an apocalyptic number.
2112211113103 is a deficient number, since it is larger than the sum of its proper divisors (542690901137).
2112211113103 is a wasteful number, since it uses less digits than its factorization.
2112211113103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9816 (or 9809 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 2112211113103 its reverse (3013111122112), we get a palindrome (5125322235215).
Subtracting 2112211113103 from its reverse (3013111122112), we obtain a palindrome (900900009009).
The spelling of 2112211113103 in words is "two trillion, one hundred twelve billion, two hundred eleven million, one hundred thirteen thousand, one hundred three".
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