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21122120147 = 160926594937
BaseRepresentation
bin10011101010111110…
…011111100111010011
32000112000222212201012
4103222332133213103
5321224230321042
613411532201135
71345266026132
oct235276374723
960460885635
1021122120147
118a59982547
1241159091ab
131cb8001a5b
141045341919
15839520e82
hex4eaf9f9d3

21122120147 has 8 divisors (see below), whose sum is σ = 21147478800. Its totient is φ = 21096779904.

The previous prime is 21122120143. The next prime is 21122120179. The reversal of 21122120147 is 74102122112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21122120147 - 22 = 21122120143 is a prime.

It is a super-2 number, since 2×211221201472 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21122120143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4275863 + ... + 4280799.

It is an arithmetic number, because the mean of its divisors is an integer number (2643434850).

Almost surely, 221122120147 is an apocalyptic number.

21122120147 is a deficient number, since it is larger than the sum of its proper divisors (25358653).

21122120147 is a wasteful number, since it uses less digits than its factorization.

21122120147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9205.

The product of its (nonzero) digits is 448, while the sum is 23.

Adding to 21122120147 its reverse (74102122112), we get a palindrome (95224242259).

The spelling of 21122120147 in words is "twenty-one billion, one hundred twenty-two million, one hundred twenty thousand, one hundred forty-seven".

Divisors: 1 1609 2659 4937 4278331 7943633 13127483 21122120147