Base | Representation |
---|---|
bin | 110000000001101011111010… |
… | …111001010110010011011011 |
3 | 1000200212122012002100122000012 |
4 | 300001223322321112103123 |
5 | 210141130340410122001 |
6 | 2025122033115032135 |
7 | 62330202550155062 |
oct | 6001537271262333 |
9 | 1020778162318005 |
10 | 211222111020251 |
11 | 61335881138211 |
12 | 1b83431573b64b |
13 | 90b220c855926 |
14 | 3a232c1a7b1d9 |
15 | 1964589e2b2bb |
hex | c01afae564db |
211222111020251 has 2 divisors, whose sum is σ = 211222111020252. Its totient is φ = 211222111020250.
The previous prime is 211222111020163. The next prime is 211222111020253. The reversal of 211222111020251 is 152020111222112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211222111020251 - 226 = 211222043911387 is a prime.
It is a super-2 number, since 2×2112221110202512 (a number of 29 digits) contains 22 as substring.
Together with 211222111020253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (211222111020253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611055510125 + 105611055510126.
It is an arithmetic number, because the mean of its divisors is an integer number (105611055510126).
Almost surely, 2211222111020251 is an apocalyptic number.
211222111020251 is a deficient number, since it is larger than the sum of its proper divisors (1).
211222111020251 is an equidigital number, since it uses as much as digits as its factorization.
211222111020251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 320, while the sum is 23.
Adding to 211222111020251 its reverse (152020111222112), we get a palindrome (363242222242363).
The spelling of 211222111020251 in words is "two hundred eleven trillion, two hundred twenty-two billion, one hundred eleven million, twenty thousand, two hundred fifty-one".
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