Base | Representation |
---|---|
bin | 1100010010111001011… |
… | …1100101011010111111 |
3 | 202012020002000110121211 |
4 | 3010232113211122333 |
5 | 11430100210111111 |
6 | 241012140305251 |
7 | 21155336461156 |
oct | 3045627453277 |
9 | 665202013554 |
10 | 211231332031 |
11 | 81645642195 |
12 | 34b30b42227 |
13 | 16bc4151185 |
14 | a31b9ac59d |
15 | 57644ab521 |
hex | 312e5e56bf |
211231332031 has 2 divisors, whose sum is σ = 211231332032. Its totient is φ = 211231332030.
The previous prime is 211231331959. The next prime is 211231332079. The reversal of 211231332031 is 130233132112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211231332031 - 215 = 211231299263 is a prime.
It is a super-2 number, since 2×2112313320312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211231331993 and 211231332011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211231312031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105615666015 + 105615666016.
It is an arithmetic number, because the mean of its divisors is an integer number (105615666016).
Almost surely, 2211231332031 is an apocalyptic number.
211231332031 is a deficient number, since it is larger than the sum of its proper divisors (1).
211231332031 is an equidigital number, since it uses as much as digits as its factorization.
211231332031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 211231332031 its reverse (130233132112), we get a palindrome (341464464143).
The spelling of 211231332031 in words is "two hundred eleven billion, two hundred thirty-one million, three hundred thirty-two thousand, thirty-one".
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