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2112410100131 = 2391843917397
BaseRepresentation
bin11110101111010101011…
…101000010000110100011
321110221111111021121011222
4132233111131002012203
5234102203441201011
64254232223325255
7305421330406352
oct36572535020643
97427444247158
102112410100131
11744960481891
122a1495a5082b
13124279175216
1474353ba1999
1539e36993ddb
hex1ebd57421a3

2112410100131 has 4 divisors (see below), whose sum is σ = 2204254017552. Its totient is φ = 2020566182712.

The previous prime is 2112410100127. The next prime is 2112410100167. The reversal of 2112410100131 is 1310010142112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2112410100131 - 22 = 2112410100127 is a prime.

It is a super-2 number, since 2×21124101001312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2111410100131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45921958676 + ... + 45921958721.

It is an arithmetic number, because the mean of its divisors is an integer number (551063504388).

Almost surely, 22112410100131 is an apocalyptic number.

2112410100131 is a deficient number, since it is larger than the sum of its proper divisors (91843917421).

2112410100131 is an equidigital number, since it uses as much as digits as its factorization.

2112410100131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91843917420.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 2112410100131 its reverse (1310010142112), we get a palindrome (3422420242243).

The spelling of 2112410100131 in words is "two trillion, one hundred twelve billion, four hundred ten million, one hundred thousand, one hundred thirty-one".

Divisors: 1 23 91843917397 2112410100131